The dilogarithm stays away from zero on the unit circle #
On the unit circle ‖Li₂ z‖ ≥ π²/12 = |Li₂(−1)|: the minimum modulus sits at the antipode. Hence the
weight-2 zeta state (populations 6/(π² n²) on the levels n) never gets halfway to an orthogonal state,
|S(θ)| ≥ 1/2 for every θ.
The proof writes Li₂(w) = w ∫∫_{(0,1)²} dx dy / (1 − xyw) on the open disk (the moments
∫∫ (xy)ⁿ = 1/(n+1)² and a sum–integral exchange), bounds each mode by
Re (1 − tz)⁻¹ ≥ (1 + t)⁻¹ for t ∈ [0,1), ‖z‖ = 1, which gives ‖Li₂(rz)‖ ≥ −Li₂(−r) for
r < 1, and lets r → 1⁻ by continuity of Li₂ on the closed disk.
Main results #
Dilog.Li₂c_eq_mul_integral: the integral representation on the open unit disk.Dilog.inv_one_add_le_re_inv: the per-mode floor.Dilog.norm_Li₂c_ge:π²/12 ≤ ‖Li₂c z‖for‖z‖ = 1.Dilog.zetaState_norm_ge_half:1/2 ≤ (6/π²) ‖Li₂c (e^{iθ})‖.