The quotient A/ℤ[α] of a quartic order with a triangular basis #
In the model of Saturation (K = ℚ(α) as ℚ⁴, ℤ[α] = ℤ⁴), an order M is given with a
triangular ℤ-basis 1, ω₁, ω₂, ω₃, ω_k = (αᵏ + P_k(α))/d_k, P_k ∈ ℤ[X] of degree < k,
0 < d₁ ∣ d₂ ∣ d₃ (the structure Louboutin.Triang; the existence of such a basis is cited from
Louboutin 2020, Prop. 10, and Cohen 1993, Cor. 4.7.6, and enters as data). That it is a basis,
that ℤ[α] ⊆ M, and the flags M ∩ V_k = ℤ + ℤω₁ + … + ℤω_k are proved. For M = A the
hypothesis d₁ = 1 is Louboutin's Theorem 13. Triang.ofData realizes every datum, so the
hypotheses are not contradictory.
Main results #
Louboutin.Triang.quotient_equiv:M/ℤ[α] ≃+ ℤ/d₁ × ℤ/d₂ × ℤ/d₃.Louboutin.Triang.quotient_equiv_T1,Louboutin.Triang.index_V2: withd₁ = 1,A/ℤ[α] ≃+ ℤ/d₂ × ℤ/d₃and[A ∩ V₂ : L₂] = d₂.Louboutin.Triang.T1_i_iff_ii,T1_ii_iff_iii,T1_iii_iff_iv,T1_iii_iff_v,Louboutin.Triang.prop_T1: the five equivalent conditions.Louboutin.Triang.T1_mod_p:p ∣ d₂iff1, α, α²are dependent over𝔽_pinA/pA.
References #
- S. R. Louboutin, On the order generated by the conjugates of an algebraic integer, in: Algebra, Logic and Number Theory, Banach Center Publ. 121 (2020), 107–124, doi:10.4064/bc121-10.
- S. R. Louboutin, When is the order generated by a cubic, quartic or quintic algebraic unit Galois invariant: three conjectures, Czechoslovak Math. J. 70 (2020), 905–919, doi:10.21136/CMJ.2020.0019-19.
- C. Marín, Orders generated by conjugates of Galois quartic integers, preprint (2026).
apow i = αⁱ in the power basis.
Equations
- Louboutin.apow i = Pi.single i 1
Instances For
V₂ = ℚ + ℚα + ℚα².
Equations
- Louboutin.V2 = { carrier := {x : Fin 4 → ℚ | x 3 = 0}, add_mem' := @Louboutin.V2._proof_1, zero_mem' := Louboutin.V2._proof_4, neg_mem' := @Louboutin.V2._proof_2 }
Instances For
L₂ = ℤ + ℤα + ℤα² = ℤ[α] ∩ V₂.
Equations
Instances For
ω₂ of the triangular basis.
Instances For
1, ω₁, ω₂, ω₃ are linearly independent: a ℤ-basis of M.
The quotient A/ℤ[α] #
Auxiliary: G ⧸ H ≃+ Q if f : P ↠ G, g : P ↠ Q and f n ∈ H ↔ g n = 0.
Equations
- One or more equations did not get rendered due to their size.
Instances For
M/ℤ[α] ≅ ℤ/d₁ × ℤ/d₂ × ℤ/d₃.
Equations
- B.quotient_equiv = Louboutin.quotEquivOf (Louboutin.Z4.addSubgroupOf M) B.combHom ⋯ (Louboutin.red3 B.d₁ B.d₂ B.d₃) ⋯ ⋯
Instances For
[A : ℤ[α]] = d₁ d₂ d₃.
[A ∩ V₂ : L₂] = d₂ #
(M ∩ V₂)/L₂ ≅ ℤ/d₁ × ℤ/d₂.
Equations
- B.quotient_equiv_V2 = Louboutin.quotEquivOf (Louboutin.L2.addSubgroupOf (M ⊓ Louboutin.V2)) B.combHom2 ⋯ (Louboutin.red2 B.d₁ B.d₂) ⋯ ⋯
Instances For
[A ∩ V₂ : L₂] = d₁ d₂.
The five conditions #
1·c₀ + α·c₁ + α²·c₂ + ω·c₃.
Equations
- Louboutin.lin ω c = c 0 • Louboutin.apow 0 + c 1 • Louboutin.apow 1 + c 2 • Louboutin.apow 2 + c 3 • ω
Instances For
(i): {1, α, α², ω} is a ℤ-basis of M (ω ∈ M and unique integer coordinates).
Instances For
(v): the set {e ≥ 1 | eM ⊆ ℤ[α]}.
Instances For
(i) ⇒ (ii).
(ii) ⇒ (iii).
(ii) ⇔ (iii).
(iii) ⇔ (iv).
min{e ≥ 1 : eM ⊆ ℤ[α]} = d₃.
(iii) ⇔ (v).
p ∣ d₂ iff 1, α, α² are linearly dependent over 𝔽_p in A/pA, that is, there are
c₀, c₁, c₂ ∈ ℤ, not all divisible by p, with c₀ + c₁α + c₂α² ∈ pA.
The proposition, for M = A with d₁ = 1 (Louboutin 2020, Thm. 13):
A/ℤ[α] ≅ ℤ/d₂ × ℤ/d₃, d₂ = [A ∩ V₂ : L₂], (i)–(v) equivalent, and the clause modulo p.
combOf as a homomorphism.
Equations
- Louboutin.combOfHom ω₁ ω₂ ω₃ = { toFun := Louboutin.combOf ω₁ ω₂ ω₃, map_zero' := ⋯, map_add' := ⋯ }
Instances For
For every 0 < d₁ ∣ d₂ ∣ d₃ and P_k, the ℤ-module generated by 1, ω₁, ω₂, ω₃ carries
a Triang structure: the hypotheses of Triang are not contradictory, for any d₂.
Equations
- One or more equations did not get rendered due to their size.