The atom certificate for the 9 × 9 pencil of the three-axes problem #
Integer data behind the proof that the 3 × 3 target matrix F of the three-axes problem is an
atom (Lemma 7.8(a)). The linear pencil Q = Q₀ + u Q_u + v Q_v + w Q_w is a 9 × 9
linearisation of F; at the point u = v = w = 2 it is invertible with det Q(2,2,2) = 256, and
the normalised coefficients K_i = 16 Q(2,2,2)⁻¹ Q_i are integer matrices. The algebra they
generate is all of M₉, witnessed by a rank-one element r ℓ (a polynomial without constant term
in K_v) together with two bases of words acting on r and on ℓ.
Determinants of the explicit 9 × 9 matrices are not computed by Laplace expansion: each one is
certified by an integer factorisation L * M.submatrix σ σ = U with L lower triangular, U upper
triangular and σ a permutation (det_eq_of_certificate), checked by decide.
Main results #
det_eq_of_certificate: ifL * M.submatrix σ σ = UwithLlower andUupper triangular over an integral domain, and∏ U i i = (∏ L i i) * dwith∏ L i i ≠ 0, thendet M = d.Q2_mul_K:Q(2,2,2) * K i = 16 • Q ifori = u, v, w;det_Q2:det Q(2,2,2) = 256.Kv_identity:K_v² (K_v² − 12 K_v + 48) = 2048 • vecMulVec r ℓ.det_wordsR:det [K_ω r]_{ω ∈ R} = 5 * 2 ^ 56;det_wordsO:det [ℓ K_ω]_{ω ∈ O} = 2 ^ 49, withK_ω = K_{ω₁} K_{ω₂} ⋯(left to right).
Determinants from triangular certificates #
The pencil #
The coefficient of a variable.
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The normalised coefficients K_i = 16 Q(2,2,2)⁻¹ Q_i #
The normalised coefficient of a variable.
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det Q(2,2,2) = 256 #
The permutation of the certificate for Q(2,2,2).
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The rank-one element: identity (7.1) #
The two bases of words: identities (7.2) #
K_ω = K_{ω₁} K_{ω₂} ⋯ (left to right).
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The words R = (∅, u, uu, vu, wu, uuu, vuu, uvu, vvu).
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The words O = (∅, u, w, uu, uv, wu, ww, uuu, uuv).
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The permutation of the certificate for matR.
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The permutation of the certificate for matO.
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