The 2 × 2 representation Θ of the quaternion curve #
Over a commutative ring R with an element ι, ι² = −1 (in the paper R = ℂ[t], ι = √−1),
let 𝐢 = diag(ι, −ι), 𝐣 = !![0,1;−1,0], 𝐤 = 𝐢𝐣. The map Θ of §4.2 sends the generators
to I + t𝐢, I + t𝐣, I + t𝐤, so ξ = x − 1, η = y − 1, ζ = z − 1 go to t𝐢, t𝐣, t𝐤.
Main results #
mi_mul_mi,mj_mul_mj,mk_mul_mk,mi_mul_mj,mj_mul_mi: the quaternion relations.smul_mul_smul_self: ifq² = −1, then(t q)² = −t² I(soξ² = η² = ζ² = −t² IunderΘ).theta_c_eq_zero:c = ξη + ηξ ↦ t²(𝐢𝐣 + 𝐣𝐢) = 0.det_one_add_smul:det(I + t q) = 1 + t²forq ∈ {𝐢, 𝐣, 𝐤}.one_add_smul_mul_one_sub_smul,one_sub_smul_mul_one_add_smul:(I + t q)(I − t q) = (1 + t²) Iin both orders, soΘ(x)⁻¹ = (I − t𝐢)/(1 + t²)wherever1 + t²is invertible.
𝐤 = 𝐢𝐣.